// Arup Guha
// 1/21/2026
// Solution to 2026 COP 3330 Program #2A: Winning Game Probability

import java.util.*;

public class wingame {

	public static void main(String[] args) {
	
		// i represents the percentage of me winning a point.
		for (int i=0; i<=100; i++) {
		
			// Turn into a double that's a decimal equivalent of i percent.
			double p = 1.0*i/100;
			
			// This is one term.
			double term = 10*Math.pow(p, 2) - 24*p + 15;
			
			// This is the probability of winning in the no deuce case.
			double nodeuce = Math.pow(p, 4)*term;
			
			// Here is the probability of winning in the deuce case. 
			
			// Split into numerator and denominator.
			double num = 20*Math.pow(p, 5)*Math.pow(1-p, 3);
			double den = 2*Math.pow(p, 2) - 2*p + 1;
			double deuce = num/den;
			
			// Just add the two terms and turn back into a percentage.
			System.out.println(i+"% \t"+ (( nodeuce+deuce)*100) + "%" );
		}
	}
}